6.2 Volumes/15: Difference between revisions

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<math>
<math>
\begin{align}
\begin{align}
\pi\int_{-1}^{1}\left(1-y^2\right)^2 dy & = \pi\int_{-1}^{1}\left(1-2y^2+y^4\right)dy \\[2ex]
\pi\int_{-1}^{1}[\left(1-y^2\right)^2\right] dy & = \pi\int_{-1}^{1}\left(1-2y^2+y^4\right)dy \\[2ex]


&= \pi\left[y-\frac{2}{3}y^3+\frac{y^5}{5}\right]\Bigg|_{-1}^{1} \\[2ex]
&= \pi\left[y-\frac{2}{3}y^3+\frac{y^5}{5}\right]\Bigg|_{-1}^{1} \\[2ex]

Revision as of 17:13, 13 December 2022

Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} \pi\int_{-1}^{1}[\left(1-y^2\right)^2\right] dy & = \pi\int_{-1}^{1}\left(1-2y^2+y^4\right)dy \\[2ex] &= \pi\left[y-\frac{2}{3}y^3+\frac{y^5}{5}\right]\Bigg|_{-1}^{1} \\[2ex] &= \pi\left[1+\frac{2}{3}+\frac{1}{5}\right]- \pi\left[-1+\frac{2}{5}-\frac{1}{5}\right] \\[2ex] &= \frac{16\pi}{15} \end{align} }