7.1 Integration By Parts/24: Difference between revisions
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\int u\,dv= u\cdot v -\int v\, du | |||
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\begin{align} | \begin{align} | ||
Revision as of 19:45, 1 December 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int u\,dv=u\cdot v-\int v\,du}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} &\int_{0}^{\pi}\underbrace{x^3\cos(x)}_{ \begin{aligned} u&=x^3 \quad \quad dv=\cos(x) \\ dv&=3x^2 \quad \quad v=\sin(x) \end{aligned}} \,dx =x^3\sin(x)-\int_{0}^{\pi} \underbrace{3x^2\sin(x)}_{ \begin{aligned} u&=3x^2 \quad \quad dv=\sin(x) \\ du&=6x \quad \quad v=-\cos(x) \end{aligned}} \,dx= x^3\sin(x)-[3x^2-\cos(x)-\int_{0}^{\pi}-6x\cos(x)\,dx]\\ =&x^3\sin(x)-3x^2\cos(x)-\int_{0}^{\pi}6x\cos(x) \end{align} }