7.1 Integration By Parts/49: Difference between revisions

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\begin{align}
\begin{align}


&&&&&&&&&&&&&&&+\int_{}^{}(n-2)\tan^{n-2}(x) \cdot \sec^{2}(x)dx                                      \quad &&&&&&+\int_{}^{}(n-2)\tan^{n-2}(x) \cdot \sec^{2}(x)dx
&&&&&&&&+\int_{}^{}(n-2)\tan^{n-2}(x) \cdot \sec^{2}(x)dx                                      \quad &&&&&&+\int_{}^{}(n-2)\tan^{n-2}(x) \cdot \sec^{2}(x)dx


\end{align}
\end{align}

Revision as of 04:23, 30 November 2022

Prove Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} \left(\tan^{n}(x)\right)dx =\frac{\tan^{n-1}x}{n-1} - \int_{}^{} \left(\tan^{n-2}x\right)dx }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} \left(\tan^{n}(x)\right)dx = \int_{}^{} \left((\tan^{2}x)(\tan^{n-2}x)\right)dx = \int_{}^{} (\sec^{2}(x)-1)\tan^{n-2}(x) dx = \int_{}^{} (\sec^{2}x)(\tan^{n-2}x)-\tan^{n-2}xdx = \int_{}^{} (\sec^{2}x)(\tan^{n-2}x) -\int_{}^{}\tan^{n-2}xdx }

Solving for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} (\sec^{2}x)(\tan^{n-2}x) }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} &u = \tan^{n-2}x \quad &dv= \sec^{2}(x)dx \\[2ex] &du = (n-2)\tan^{n-3}(x) \cdot \sec^{2}(x)dx \quad &v= \tan(x) \\[2ex] \end{align} }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{}^{} (\sec^{2}x)(\tan^{n-2}x)dx = \tan^{n-2}(x) \cdot \tan(x) - \int_{}^{} (n-2)\tan^{n-3}(x)\sec^{2} \cdot \tan(x)dx \\[2ex] = \tan^{n-1}(x) - \int_{}^{} (n-2)\tan^{n-2}(x)\sec^{2}dx \\[2ex] \tan^{n-1}(x) - \int_{}^{} (n-2)\tan^{n-2}(x)\sec^{2}dx = \int_{}^{} (\sec^{2}x)(\tan^{n-2}x)dx \\[2ex] \end{align} }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} &&&&&&&&+\int_{}^{}(n-2)\tan^{n-2}(x) \cdot \sec^{2}(x)dx \quad &&&&&&+\int_{}^{}(n-2)\tan^{n-2}(x) \cdot \sec^{2}(x)dx \end{align} }

Note: Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \tan^{2}(x) = \sec^{2}(x)-1 \end{align} }