7.1 Integration By Parts/51b: Difference between revisions

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\begin{aligned}
\begin{aligned}
u & = \ln^{2}{(x)}  & x &= \tfrac{1}{\sqrt{2}}(u+v) \\[0.6ex]
u & = \ln^{2}{(x)}  & dv &= dx \\[0.6ex]
du & = \tfrac{2}{\ln{(x)}}dx  & y &= \tfrac{1}{\sqrt{2}}(u-v)
du & = \tfrac{2}{\ln{(x)}}dx  & v &= x
\end{aligned}
\end{aligned}
}
}

Revision as of 17:50, 29 November 2022