7.1 Integration By Parts/51b: Difference between revisions
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\begin{aligned} | \begin{aligned} | ||
u & = \ln^{2}{(x)} & x &= \tfrac{1}{\sqrt{2}}(u+v) \\[0.6ex] | u & = \ln^{2}{(x)} & x &= \tfrac{1}{\sqrt{2}}(u+v) \\[0.6ex] | ||
du & = \tfrac{2}{\ln{(x)}}dx & y &= \tfrac{1}{\sqrt{2}}(u-v) | |||
\end{aligned} | \end{aligned} | ||
} | } |
Revision as of 17:49, 29 November 2022