7.1 Integration By Parts/51b: Difference between revisions

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\begin{aligned}
\begin{aligned}
u &= \ln^{2}{x} \quad dv=dx \\[2ex]
u &= \ln^{2}{x} \quad dv=dx \\[2ex]
du &= \frac{2}{x}\ln{x}dx \quad v=x \\[2ex]
du &= \frac{2}{x}\ln{(x)}dx \quad v=x \\[2ex]


\end{aligned}
\end{aligned}

Revision as of 17:46, 29 November 2022