7.1 Integration By Parts/30: Difference between revisions

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<math>
<math>
\begin{align}
Now, we need to substitute u back
u &= 4+r^{2} \\[2ex]
 
\end{align}
</math>
</math>

Revision as of 12:29, 29 November 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{1}\frac{r^{3}}{\sqrt{4+r^{2}}}\cdot dr }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= 4+r^{2} \\[2ex] r^{2} &= u-4 \\[2ex] 2r\cdot dr &= du \\[2ex] \end{align} }

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{0}^{1}{\frac {r^{3}}{\sqrt {4+r^{2}}}}\cdot dr~~~=~~~\int _{0}^{1}{\frac {r}{2{\sqrt {u}}}}\cdot du~~~=~~~\int _{0}^{1}{\frac {u-4}{2{\sqrt {u}}}}\cdot du~~~=~~~{\frac {}{}}{\frac {1}{2}}\int _{0}^{1}\left({\frac {u}{\sqrt {u}}}-{\frac {4}{\sqrt {u}}}\right)\cdot du~~~=~~~}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{1}{2} \left [ \left (\frac{u^{\frac{1}{2}+1}}{\frac{1}{2}+1} \right ) - \left ( \frac{u^{-\frac{1}{2}+1}}{-\frac{1}{2}+1} \right ) \right ] ~~~ = ~~~ \frac{1}{2} \left [ \left (\frac{u^{\frac{3}{2}}}{\frac{3}{2}} \right ) - 4\left ( \frac{u^{\frac{1}{2} }}{\frac{1}{2}} \right )\right ] ~~~ = ~~~ \frac{u^{\frac{3}{2}}}{3} - 4u^{\frac{1}{2}} }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle Now, we need to substitute u back }