7.1 Integration By Parts/30: Difference between revisions
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<math> \int_{0}^{1}\frac{r^{3}}{\sqrt{4+r^{2}}}\cdot dr ~~~ = ~~~ \int_{0}^{1}\frac{r}{2\sqrt{u}}\cdot dr ~~~ = ~~~ \int_{0}^{1}\frac{u-4}{2\sqrt{u}}\cdot dr </math> | <math> \int_{0}^{1}\frac{r^{3}}{\sqrt{4+r^{2}}}\cdot dr ~~~ = ~~~ \int_{0}^{1}\frac{r}{2\sqrt{u}}\cdot dr ~~~ = ~~~ \int_{0}^{1}\frac{u-4}{2\sqrt{u}}\cdot dr ~~~ = ~~~ \frac{}{}\frac{1}{2} \int_{0}^{1} \left (\frac{u}{\sqrt{u}} - \frac{4}{\sqrt{u}} \right ) \cdot dr </math> | ||
Revision as of 12:04, 29 November 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{1}\frac{r^{3}}{\sqrt{4+r^{2}}}\cdot dr }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= 4+r^{2} \\[2ex] r^{2} &= u-4 \\[2ex] 2r\cdot dr &= du \\[2ex] \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{1}\frac{r^{3}}{\sqrt{4+r^{2}}}\cdot dr ~~~ = ~~~ \int_{0}^{1}\frac{r}{2\sqrt{u}}\cdot dr ~~~ = ~~~ \int_{0}^{1}\frac{u-4}{2\sqrt{u}}\cdot dr ~~~ = ~~~ \frac{}{}\frac{1}{2} \int_{0}^{1} \left (\frac{u}{\sqrt{u}} - \frac{4}{\sqrt{u}} \right ) \cdot dr }