7.1 Integration By Parts/30: Difference between revisions

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r^{2} &= u-4 \\[2ex]
r^{2} &= u-4 \\[2ex]


2r\cdotdr &= du; \\[2ex]
2r \cdotdr &= du \\[2ex]


du &= \frac{1}{\sqrt{1-x^2}}\;dx \\[2ex]
du &= \frac{1}{\sqrt{1-x^2}}\;dx \\[2ex]

Revision as of 11:53, 29 November 2022


Failed to parse (unknown function "\cdotdr"): {\displaystyle \begin{align} u &= 4+r^{2} \\[2ex] r^{2} &= u-4 \\[2ex] 2r \cdotdr &= du \\[2ex] du &= \frac{1}{\sqrt{1-x^2}}\;dx \\[2ex] \end{align} }

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{0}^{1}{\frac {r^{3}}{\sqrt {4+r^{2}}}}\cdot dr~~~=~~~\int _{0}^{1}r^{3}\cdot {\frac {1}{\sqrt {4+r^{2}}}}\cdot dr}