7.1 Integration By Parts/11: Difference between revisions
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\begin{align} | \begin{align} | ||
& u=1+16t^{2} \\[1ex] | & \qquad u=1+16t^{2} \\[1ex] | ||
& du=32t dt \\[1ex] | & du=32t dt \\[1ex] | ||
& \frac{1}{32}du=t dt | & \frac{1}{32}du=t dt |
Revision as of 05:13, 29 November 2022