7.1 Integration By Parts/48: Difference between revisions

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\begin{align}
\begin{align}
u &= x^{n} \quad dv= e^{x} dx \\[2ex]
u &= x^{n} \quad & dv= e^{x} dx \\[2ex]
du &=n x^{n-1} dx      \quad v=e^x \\[2ex]
du &=n x^{n-1} dx      \quad & v=e^x \\[2ex]


\end{align}
\end{align}

Revision as of 04:38, 29 November 2022