7.1 Integration By Parts/20: Difference between revisions
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(Undo revision 5641 by Ricardom59381@students.laalliance.org (talk)) Tag: Undo |
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&= (x^{2}+1)(-e^{-x})\bigg|_{0}^{1} - 2\int_{0}^{1} (-e^{x})(x)dx \\[2ex] | &= (x^{2}+1)(-e^{-x})\bigg|_{0}^{1} - 2\int_{0}^{1} (-e^{x})(x)dx \\[2ex] | ||
\ | &= x \ln(x)^{n} - \int_{}^{} \left(n \ln(x)^{n-1} \right)dx \\[2ex] | ||
&= x \ln(x)^{n} - n \int_{}^{} \left(\ln(x)^{n-1} \right)dx \\[2ex] | |||
\end{align} | \end{align} | ||
</math> | </math> |
Revision as of 03:49, 29 November 2022