7.1 Integration By Parts/13: Difference between revisions
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<math>\int t\sec^2\left(2t\right) dt </math> | <math>\int t\sec^2\left(2t\right) dt </math> | ||
<math>u = t \qquad dv = \sec^2\left(2t\right) \qquad \int\sec^2\left(2t\right)dt</math> <br><br> | <math>u = t \qquad dv = \sec^2\left(2t\right) \qquad & = \int\sec^2\left(2t\right)dt | ||
&= \frac{1}{2}\int\sec^2\left(u\right)du | |||
</math> <br><br> | |||
<math>du = dt \qquad v = \frac{1}{2}\tan\left(2t\right)</math> | <math>du = dt \qquad v = \frac{1}{2}\tan\left(2t\right)</math> | ||
Revision as of 03:00, 29 November 2022
Failed to parse (syntax error): {\displaystyle u = t \qquad dv = \sec^2\left(2t\right) \qquad & = \int\sec^2\left(2t\right)dt &= \frac{1}{2}\int\sec^2\left(u\right)du }
