6.2 Volumes/3

$y={\frac {1}{x}},x=1,x=2,y=0;{\text{about the x-axis}}$

${\begin{aligned}\pi \int _{1}^{2}\left[\left({\frac {1}{x}}\right)^{2}\right]dx&=\pi \int _{1}^{2}\left[\left({\frac {1}{x^{2}}}\right)\right]dx&=\pi \left[-{\frac {1}{x}}\right]\end{aligned}}$