7.1 Integration By Parts/54: Difference between revisions

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\begin{align}
\begin{align}


5\ln(x)&=x\ln(x)\\[2ex]
5\ln(x)&=x\ln(x)\\[1ex]
&=5 \\[1ex]
&=5 \\[1ex]
&=1 \\[1ex]
&=1 \\[1ex]

Revision as of 23:23, 28 November 2022