7.1 Integration By Parts/54: Difference between revisions

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5\ln(x)&=x\ln(x)\\[2ex]
5\ln(x)&=x\ln(x)\\[2ex]
&=5 \\[2ex]
&=5 \\[ex]
&=1 \\[2ex]
&=1 \\[ex]


\end{align}
\end{align}
</math>
</math>

Revision as of 23:23, 28 November 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. TeX parse error: Bracket argument to \\ must be a dimension"): {\displaystyle {\begin{aligned}5\ln(x)&=x\ln(x)\\[2ex]&=5\\[ex]&=1\\[ex]\end{aligned}}}