6.5 Average Value of a Function/1: Difference between revisions
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f(x) = 4x-x^2, (0, 4) | f(x) = 4x-x^2, (0, 4) | ||
</math> | </math> | ||
<math> | |||
\begin{align} | |||
f_{avg} &= \frac{1}{4} \int_{0}^{4} (4x-x^2) dx \\[2ex] | |||
Revision as of 23:07, 28 November 2022
Find the average value of the function on the given interval.
<math>
\begin{align} f_{avg} &= \frac{1}{4} \int_{0}^{4} (4x-x^2) dx \\[2ex]