7.1 Integration By Parts/47: Difference between revisions

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\begin{align}
\begin{align}
u &= \ln(x)^{n} \quad dv= 1dx \\[2ex]
u &= \ln(x)^{n} \quad dv= 1dx \\[2ex]
du &=1dx        \quad v=x \\[2ex]
du &=1dx        \qquad v=x \\[2ex]


\end{align}
\end{align}
</math>
</math>

Revision as of 19:05, 28 November 2022