6.5 Average Value of a Function/1: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 2: | Line 2: | ||
<math> | <math> | ||
f(x) = 4x-x^2 (0, 4) | f(x) = 4x-x^2, (0, 4) | ||
</math> | </math> | ||
<math> | <math> | ||
\begin{align} | \begin{align} | ||
Revision as of 17:55, 28 November 2022
Find the average value of the function on the given interval.
<math> \begin{align}