7.1 Integration By Parts/27: Difference between revisions

Revision as of 22:55, 25 November 2022

$f'(x)=\int _{0}^{\frac {1}{2}}\cos ^{-1}(x)\cdot dx$

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	<math> f'(x)= \int_{\frac{1}{2}~~}^{0~~}\cos^{-1}(x)\cdot dx </math> <br><br>		<math> f'(x)= \int_{0}^{\frac{1}{2}}\cos^{-1}(x)\cdot dx </math> <br><br>