6.2 Volumes/1: Difference between revisions

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<math>
<math>
\begin{align}
y=2-\frac{1}{2}x \\[2ex]
y=2-\frac{1}{2}x \\[2ex]
& \text{y = 0},  \text{x = 1}, \text{x = 2}; \text{about the x-axis}
& \text{y = 0},  \text{x = 1}, \text{x = 2}; \text{about the x-axis}
\end{align}
</math>
</math>



Revision as of 04:03, 24 November 2022

Failed to parse (syntax error): {\displaystyle y=2-\frac{1}{2}x \\[2ex] & \text{y = 0}, \text{x = 1}, \text{x = 2}; \text{about the x-axis} }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \pi\int_1^2\left[\left(2-\frac{1}{2}x\right)^2\right]dx & = \pi\int_1^2\left[\left(4-2x+\frac{1}{4}x^2\right)\right]dx \\[2ex] &= \pi\left[4x-x^2+\frac{1}{12}x^3\right]\Bigg|_1^2 \\[2ex] &= \pi\left[4(2)-(2)^2+\frac{1}{12}(2)^3-\left(4(1)-(1)^2+\frac{1}{12}(1)^3\right)\right] \\[2ex] &= \pi\left[8-4+\frac{8}{12}-\left(4-1+\frac{1}{12}\right)\right] \\[2ex] &= \pi\left[4+\frac{8}{12}-3-\frac{1}{12}\right]= \pi\left[1+\frac{7}{12}\right] \\[2ex] &= \pi\left[\frac{12}{12}+\frac{7}{12}\right]= \pi\left[\frac{19}{12}\right] \\[2ex] &= \frac{19\pi}{12} \end{align} }