7.1 Integration By Parts/36: Difference between revisions

Revision as of 02:28, 23 November 2022

$\int _{0}^{\pi }e^{cost}(sin2t)dt$ = $\int _{0}^{\pi }e^{cost}(2sintcost)dt$ = ${-2}\int _{cos0}^{cos\pi }e^{u}{u}du$

${u}$ = $(cost)$

${du}$ = $(-sint)dt$

${-du}$ = $(sint)dt$

Revision as of 02:24, 23 November 2022 (view source) Debbier70425@students.laalliance.org (talk \| contribs) No edit summary ← Older edit		Revision as of 02:28, 23 November 2022 (view source) Debbier70425@students.laalliance.org (talk \| contribs) No edit summary Newer edit →
Line 1:		Line 1:
	<math>\int_{0}^{\pi}e^{cost}(sin2t)dt</math> = <math>\int_{0}^{\pi}e^{cost}(2sintcost)dt</math>		<math>\int_{0}^{\pi}e^{cost}(sin2t)dt</math> = <math>\int_{0}^{\pi}e^{cost}(2sintcost)dt</math> = <math>{-2}\int_{cos0}^{cos\pi}e^{u}{u}du</math>