5.5 The Substitution Rule/55: Difference between revisions
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\int_{0}^{\pi} \sec^2\left(\frac{t}{4}\right)dt | \int_{0}^{\pi} \sec^2\left(\frac{t}{4}\right)dt | ||
&= 4\int_{0}^{\pi} \sec^2(u)du \\[2ex] | |||
&= 4\cdot \tan^2(u) = 4\cdot \tan^2\left(\frac{t}{4}\right)\bigg|_{0}^{\pi} \\[2ex] | |||
&= 4\cdot \tan^2\left(\frac{\pi}{4}\right)-4\cdot \tan^2\left(\frac{0}{4}\right) \\[2ex] | |||
&= 4-0 \\[2ex] | |||
&= 4 | |||
\end{align} | \end{align} | ||
</math> | </math> | ||
Latest revision as of 16:19, 4 October 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{\pi} \sec^2\left(\frac{t}{4}\right)dt }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= \frac{t}{4} \\[2ex] du &= \frac{1}{4}dt \\[2ex] 4du &=dx \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{0}^{\pi} \sec^2\left(\frac{t}{4}\right)dt &= 4\int_{0}^{\pi} \sec^2(u)du \\[2ex] &= 4\cdot \tan^2(u) = 4\cdot \tan^2\left(\frac{t}{4}\right)\bigg|_{0}^{\pi} \\[2ex] &= 4\cdot \tan^2\left(\frac{\pi}{4}\right)-4\cdot \tan^2\left(\frac{0}{4}\right) \\[2ex] &= 4-0 \\[2ex] &= 4 \end{align} }