5.5 The Substitution Rule/33: Difference between revisions

From Mr. V Wiki Math
Jump to navigation Jump to search
No edit summary
No edit summary
Line 8: Line 8:
u &= \cot{(x)} \\[2ex]
u &= \cot{(x)} \\[2ex]
du &= -csc^2{(x)}dx \\[2ex]
du &= -csc^2{(x)}dx \\[2ex]
dx &= \frac{du}{-csc^2{(x)}} \\[2ex]
-du &= -csc^2{(x)}dx \\[2ex]
\end{align}
\end{align}
</math>
</math>

Revision as of 16:27, 29 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int {\sqrt{\cot(x)}} \csc^2{(x)}dx }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= \cot{(x)} \\[2ex] du &= -csc^2{(x)}dx \\[2ex] -du &= -csc^2{(x)}dx \\[2ex] \end{align} }


Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&=\int {\sqrt {u}}\csc ^{2}{(x)}{\frac {du}{-csc{(x)}}}&=-\int {({\sqrt {u}})}du\\[2ex]&=\int (u^{\frac {1}{2}})du\\[2ex]&=-{\frac {2}{3}}u+c\\[2ex]&=-{\frac {2}{3}}(\cot {(x)})^{\frac {3}{2}}+c\end{aligned}}}