6.1 Areas Between Curves/12: Difference between revisions
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\begin{align} | \begin{align} | ||
&= \left[\frac{4x^2}{2}\right]\Bigg|_{0}^{2} \\[2ex] | &= \left[\frac{4x^2}{2}\right]\Bigg|_{0}^{2} \\[2ex] | ||
&= \left[ | &= \left[2x^2\right]\Bigg|_{0}^{2} \\[2ex] | ||
&= \left[16-\frac{16}{3}\right]-\left[-16+\frac{16}{3}\right] = 32-\frac{32}{3} \\[2ex] | &= \left[16-\frac{16}{3}\right]-\left[-16+\frac{16}{3}\right] = 32-\frac{32}{3} \\[2ex] | ||
&= \frac{64}{3} | &= \frac{64}{3} | ||
Revision as of 23:24, 22 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \color{red}\mathbf{y=x^2} & \color{royalblue}\mathbf{y=4x-x^2} \\ & x=0 & x=2 \\ \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{2} \left[(4x-x^2) - (x^2)\right] dx}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} 4-x^2 &= x^2 \\ 4x-2x^2 &= 0 \\ 2x(2-x) &= 0 \\ x &= 0& x = 2 \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{2} \left[(4x-x^2) - (x^2)\right]dx = \int_{0}^{2} (4x)dx}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} &= \left[\frac{4x^2}{2}\right]\Bigg|_{0}^{2} \\[2ex] &= \left[2x^2\right]\Bigg|_{0}^{2} \\[2ex] &= \left[16-\frac{16}{3}\right]-\left[-16+\frac{16}{3}\right] = 32-\frac{32}{3} \\[2ex] &= \frac{64}{3} \end{align} }