5.5 The Substitution Rule/11: Difference between revisions

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&= \frac{1}{2}({\frac{2u^\frac{3}{2}}{3}}) + C \\[2ex]
&= \frac{1}{2}({\frac{2u^\frac{3}{2}}{3}}) + C \\[2ex]
&= \frac{1}{3}(u^{\frac{3}{2}}) + C \\[2ex]
&= \frac{1}{3}(2x+x^{2})^{\frac{3}{2}} + C \\[2ex]


\end{align}
\end{align}
</math>
</math>

Latest revision as of 21:28, 22 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int (x+1)\sqrt{2x+x^{2}}dx }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &=2x+x^{2} \\[2ex] du &=2+2x dx \\[2ex] \frac{1}{2}du &=x+1 \end{align} }


Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int (x+1){\sqrt {2x+x^{2}}}dx&={\frac {1}{2}}\int {\sqrt {u}}du={\frac {1}{2}}\int u^{\frac {1}{2}}du\\[2ex]&={\frac {1}{2}}({\frac {2u^{\frac {3}{2}}}{3}})+C\\[2ex]&={\frac {1}{3}}(u^{\frac {3}{2}})+C\\[2ex]&={\frac {1}{3}}(2x+x^{2})^{\frac {3}{2}}+C\\[2ex]\end{aligned}}}