5.4 Indefinite Integrals and the Net Change Theorem/43: Difference between revisions
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<math> | <math> | ||
\ | \begin{align} | ||
\int_{-1}^{2}(x-2|x|)dx &= \int_{-1}^{0}(x-2(-x))dx + \int_{0}^{2}(x-2(x))dx = \int_{-1}^{0}3x\,dx - \int_{0}^{2}x\,dx \\[2ex] | |||
&= \left(\frac{3x^2}{2} \right)\bigg|_{-1}^{0} - \left(\frac{x^2}{2} \right)\bigg|_{0}^{2} \\[2ex] | |||
&= \left[\frac{3(0)^2}{2}-\frac{3(-1)^2}{2}\right]-\left[\frac{(2)^2}{2} - \frac{(0)^2}{2}\right] \\[2ex] | |||
&= \left[-\frac{3}{2}\right]-\left[\frac{4}{2}\right] \\[2ex] | |||
&= -\frac{7}{2} \\[2ex] | |||
\end{align} | |||
</math> | </math> | ||
Latest revision as of 19:42, 21 September 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int _{-1}^{2}(x-2|x|)dx&=\int _{-1}^{0}(x-2(-x))dx+\int _{0}^{2}(x-2(x))dx=\int _{-1}^{0}3x\,dx-\int _{0}^{2}x\,dx\\[2ex]&=\left({\frac {3x^{2}}{2}}\right){\bigg |}_{-1}^{0}-\left({\frac {x^{2}}{2}}\right){\bigg |}_{0}^{2}\\[2ex]&=\left[{\frac {3(0)^{2}}{2}}-{\frac {3(-1)^{2}}{2}}\right]-\left[{\frac {(2)^{2}}{2}}-{\frac {(0)^{2}}{2}}\right]\\[2ex]&=\left[-{\frac {3}{2}}\right]-\left[{\frac {4}{2}}\right]\\[2ex]&=-{\frac {7}{2}}\\[2ex]\end{aligned}}}