5.5 The Substitution Rule/61: Difference between revisions

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<math>\int_{0}^{13}\frac{dx}{\sqrt[3]{(1+2x)^2}}</math>
<math>\int_{0}^{13}\frac{dx}{\sqrt[3]{(1+2x)^2}}</math>
=<math>\int_{0}^{13}\frac{1}{2^3\sqrt{t^2}}dt</math>
= <math>\int_{0}^{13}\frac{1}{2^3\sqrt{t^2}}dt</math>
=<math>\frac{1}{2}\int_{0}^{13}\frac{1}{\sqrt[3]{t^2}}dt</math>
= <math>\frac{1}{2}\int_{0}^{13}\frac{1}{\sqrt[3]{t^2}}dt</math>

Revision as of 19:22, 20 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{13}\frac{dx}{\sqrt[3]{(1+2x)^2}}} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{13}\frac{1}{2^3\sqrt{t^2}}dt} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{1}{2}\int_{0}^{13}\frac{1}{\sqrt[3]{t^2}}dt}