5.5 The Substitution Rule/37: Difference between revisions

From Mr. V Wiki Math
Jump to navigation Jump to search
No edit summary
No edit summary
Line 22: Line 22:
&= \int \frac{1}{{u}}(du) \\[2ex]
&= \int \frac{1}{{u}}(du) \\[2ex]


\text{Note: } \int \frac{1}{{x}}\;dx= ln(x)+C \\[2ex]
\text{Note: } \int \frac{1}{{x}}\;dx= \ln(x)+C \\[2ex]


&= \left| \ln(u) \right| + C \\[2ex]
&= \left| \ln(u) \right| + C \\[2ex]

Revision as of 19:13, 20 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int \cot(x)dx = \int \frac{\cos(x)}{\sin(x)}dx }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= \sin(x) \\[2ex] du &= \cos(x)\;dx \\[2ex] \end{align} }


Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int {\frac {\cos(x)}{\sin(x)}}dx&=\int {\frac {1}{\sin(x)}}\cos(x)\;dx=\int {\frac {1}{\sin(x)}}(\cos(x)\;dx)\\[2ex]&=\int {\frac {1}{u}}(du)\\[2ex]{\text{Note: }}\int {\frac {1}{x}}\;dx=\ln(x)+C\\[2ex]&=\left|\ln(u)\right|+C\\[2ex]&=\left|\ln(\sin(x))\right|+C\\[2ex]\end{aligned}}}