5.5 The Substitution Rule/41: Difference between revisions

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u &= \arcsin {x}
u &= \arcsin {x}
   \\[2ex]
   \\[2ex]
du &= \frac{1}{\sqrt{1-x^2}} dx \\[2ex]
du &= \frac{1}{\sqrt{1-x^2}}\;dx \\[2ex]


\end{align}
\end{align}

Revision as of 23:15, 13 September 2022


Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}u&=\arcsin {x}\\[2ex]du&={\frac {1}{\sqrt {1-x^{2}}}}\;dx\\[2ex]\end{aligned}}}


Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int {\frac {1}{\sqrt {1-x^{2}}}}{\frac {1}{\arcsin {x}}}&=\int {\frac {1}{u}}du\\[2ex]&=\ln |u|+c\\[2ex]&=\ln |\arcsin {x}|+c\\[2ex]\end{aligned}}}