5.5 The Substitution Rule/21: Difference between revisions

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\begin{align}
\begin{align}


u &= \sqrt{u}
u &= \sqrt{u} \\[2ex]
  \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]
2du &= \frac{1}{\sqrt{t}} dx
2du &= \frac{1}{\sqrt{t}} dx
\end{align}
\end{align}
</math>
</math>

Revision as of 15:36, 7 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int \frac{\cos{(\sqrt{t})}}{\sqrt{t}} dt = 2\int \cos {u} du = 2 \sin{u}+c = 2 \sin(\sqrt{u}) + c }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= \sqrt{u} \\[2ex] du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex] 2du &= \frac{1}{\sqrt{t}} dx \end{align} }