5.5 The Substitution Rule/41: Difference between revisions

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Line 8: Line 8:
\begin{align}
\begin{align}


u &= \sqrt{u}
u &= \arcsin {x}
   \\[2ex]
   \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]

Revision as of 09:06, 7 September 2022


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= \arcsin {x} \\[2ex] du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex] 2du &= \frac{1}{\sqrt{t}} dx \end{align} }