5.3 The Fundamental Theorem of Calculus/9

$g(y)=\int _{2}^{y}t^{2}\sin {(t)}dt$

${\frac {d}{dy}}\left[g(y)\right]={\frac {d}{dy}}\left[\int _{2}^{y}t^{2}\sin {(t)}dt\right]=1\cdot ((y)^{2}\sin {y})-0\cdot ((0)^{2}\sin {(2)})=y^{2}\sin {(y)}$

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \text{Therefore, } g'(y) = y^{2}\sin{(y)} }