5.5 The Substitution Rule/69: Difference between revisions
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<math> | <math> | ||
\begin{align} | \begin{align} | ||
\int_{0}^{1} \left(\frac{e^z + 1}{e^z + z}\right) &= \int_{ | \int_{0}^{1} \left(\frac{e^z + 1}{e^z + z}\right) &= \int_{}^{} \left((e^z +1) (\frac{1}{e^z +z}) \right) | ||
u= e^z + z | |||
du= e^z +1 | |||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 15:47, 6 September 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int _{0}^{1}\left({\frac {e^{z}+1}{e^{z}+z}}\right)&=\int _{}^{}\left((e^{z}+1)({\frac {1}{e^{z}+z}})\right)u=e^{z}+zdu=e^{z}+1\end{aligned}}}