5.5 The Substitution Rule/15: Difference between revisions
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'<math>\begin{align} \ \int sin(\pi t) dt = \int sin(u)(\frac{1}{\pi}du)= \int \frac{1}{\pi} (-cosu) + c = | '<math>\begin{align} \ \int sin(\pi t) dt = \int sin(u)(\frac{1}{\pi}du)= \int \frac{1}{\pi} (-cosu) + c = \int - \frac{1}{\pi} cos (\pi t) + c | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 05:36, 5 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \ \int sin(\pi t) dt \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} let \; u &=\pi t \\[2ex] du &= \pi dx \\[2ex] \frac{1}{\pi}du &= dx \end{align} }
'Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \ \int sin(\pi t) dt = \int sin(u)(\frac{1}{\pi}du)= \int \frac{1}{\pi} (-cosu) + c = \int - \frac{1}{\pi} cos (\pi t) + c \end{align} }