5.5 The Substitution Rule/15: Difference between revisions

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Line 6: Line 6:
\begin{align}
\begin{align}


let \hspace u &=\pi t \\[2ex]
let \space u &=\pi t \\[2ex]
du &= \pi dx \\[2ex]
du &= \pi dx \\[2ex]
\frac{1}{\pi}du &= dx
\frac{1}{\pi}du &= dx

Revision as of 04:37, 5 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \ \int sin(\pi t) dt \end{align} }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} let \space u &=\pi t \\[2ex] du &= \pi dx \\[2ex] \frac{1}{\pi}du &= dx \end{align} }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \ \int sin(\pi t) dt = \int sin(u)(\frac{1}{\pi}du)= \int \frac{1}{\pi} (-cos(u))+C = \int - \frac{1}{\pi} cos \pi t + C \end{align} }