5.5 The Substitution Rule/1: Difference between revisions

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\begin{align}
\begin{align}


& \int{e^{-x}} dx , [2ex]u=-x \\[2ex]  
& \int{e^{-x}} dx ,\\[2ex]u=-x \\[2ex]  


& u=-x \\ [2ex]
& u=-x \\ [2ex]

Revision as of 19:44, 1 September 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int {e^{-x}}dx,\\[2ex]u=-x\\[2ex]&u=-x\\[2ex]&du=-dx\\[2ex]&\int {e^{-x}}dx\\[2ex]&=-\int {e^{u}}du\\[2ex]&=-e^{u}du\\[2ex]&=-e^{-x}+C\\[2ex]\end{aligned}}}