5.5 The Substitution Rule/1: Difference between revisions

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& \int{e^{-x}} dx =  
& \int{e^{-x}} dx =  


&= -\int{e^{u}} du =  
& -\int{e^{u}} du =  


&= -e^{u} du =  
& -e^{u} du =  


&= -e^{-x}+C
& -e^{-x}+C


\end{align}
\end{align}
</math>
</math>

Revision as of 19:37, 1 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int{e^{-x}} dx , u=-x \\[2ex] & u=-x \\ [2ex] & du=-dx\\ [2ex] & \int{e^{-x}} dx = & -\int{e^{u}} du = & -e^{u} du = & -e^{-x}+C \end{align} }