5.5 The Substitution Rule/1: Difference between revisions

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& u=-x \\ [2ex]
& u=-x \\ [2ex]


& du=-1dx=\\ [2ex]
& du=-1dx\\ [2ex]


& \int{e^{-x}} dx \\[2ex]
& \int{e^{-x}} dx = \\[2ex]


& -\int{e^{u}} du \\ [2ex]
& -\int{e^{u}} du \\ [2ex]

Revision as of 19:28, 1 September 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int {e^{-x}}dx,u=-x\\[2ex]&u=-x\\[2ex]&du=-1dx\\[2ex]&\int {e^{-x}}dx=\\[2ex]&-\int {e^{u}}du\\[2ex]&-e^{u}du\\[2ex]&-e^{-x}+C\end{aligned}}}