6.2 Trigonometric Functions: Unit Circle Approach/15: Difference between revisions

From Mr. V Wiki Math
Jump to navigation Jump to search
(Created page with ":<math> \begin{align} -\frac{2}{5},\frac\sqrt{21}{5} \sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex] \cos{(t)} &= \frac\{x}{r} & \sec{(t)} &= \frac{r}{x}\\[2ex] \tan{(t)} &= \frac{y}{x} & \cot{(t)} &= \frac{x}{y} \\[2ex] \end{align} </math> \end{align} </math>")
 
No edit summary
Line 5: Line 5:


\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex]
\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex]
\cos{(t)} &= \frac\{x}{r} & \sec{(t)} &= \frac{r}{x}\\[2ex]  
\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]  
\tan{(t)} &= \frac{y}{x} & \cot{(t)} &= \frac{x}{y} \\[2ex]
\tan{(t)} &= \frac\sqrt-{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]


\end{align}
\end{align}

Revision as of 18:53, 30 August 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}-{\frac {2}{5}},{\frac {\sqrt {21}}{5}}\sin {(t)}&={\frac {\sqrt {21}}{5}}&\csc {(t)}&={\frac {r}{y}}\\[2ex]\cos {(t)}&=-{\frac {2}{5}}&\sec {(t)}&={\frac {r}{x}}\\[2ex]\tan {(t)}&={\frac {\sqrt {-}}{21}}{2}&\cot {(t)}&={\frac {x}{y}}\\[2ex]\end{aligned}}}


\end{align} </math>