5.4 Indefinite Integrals and the Net Change Theorem/39: Difference between revisions
No edit summary |
No edit summary |
||
| Line 7: | Line 7: | ||
Add one to the exponents and divide by the new exponent | Add one to the exponents and divide by the new exponent | ||
<math>\int_{1}^{64}\frac{x^{1/2}}{\frac{1}{2}}+ \frac{x^{5/6}}{\frac{5}{6}}</math> = | <math>\int_{1}^{64}\frac{x^{1/2}}{\frac{1}{2}}+ \frac{x^{5/6}}{\frac{5}{6}}</math> = <math>\int_{1}^{64}2x^{\frac{1}{2}} | ||
Revision as of 09:36, 29 August 2022
![{\displaystyle \int _{1}^{64}{\frac {1+{\sqrt[{3}]{x}}}{\sqrt {x}}}dx}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/cdb02981593f318bab17caae838949d55b200cb6)
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}\frac{1}{x^{1/2}}} + Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}\frac{x^{1/3}}{x^{1/2}}}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}x^{-1/2}+x^{1/3-1/2}} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}x^{-1/2}+x^{-1/6}}
Add one to the exponents and divide by the new exponent
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}\frac{x^{1/2}}{\frac{1}{2}}+ \frac{x^{5/6}}{\frac{5}{6}}} = <math>\int_{1}^{64}2x^{\frac{1}{2}}