5.4 Indefinite Integrals and the Net Change Theorem/39: Difference between revisions

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<math>\int_{1}^{64}\frac{1}{x^{1/2}}</math> + <math>\int_{1}^{64}\frac{x^{1/3}}{x^{1/2}}</math>
<math>\int_{1}^{64}\frac{1}{x^{1/2}}</math> + <math>\int_{1}^{64}\frac{x^{1/3}}{x^{1/2}}</math>


<math>\int_{1}^{64}x^{-1/2}+x^{1/3-1/2}</math>  
<math>\int_{1}^{64}x^{-1/2}+x^{1/3-1/2}</math> = <math>\int_{1}^{64}x^{-1/2}+x^{-1/6}</math>


Add one to the exponents and divide by the new exponent
Add one to the exponents and divide by the new exponent

Revision as of 09:20, 29 August 2022

+ Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}\frac{x^{1/3}}{x^{1/2}}}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}x^{-1/2}+x^{1/3-1/2}} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}x^{-1/2}+x^{-1/6}}

Add one to the exponents and divide by the new exponent