5.4 Indefinite Integrals and the Net Change Theorem/39: Difference between revisions
No edit summary |
No edit summary |
||
| Line 3: | Line 3: | ||
<math>\int_{1}^{64}\frac{1}{x^{1/2}}</math> + <math>\int_{1}^{64}\frac{x^{1/3}}{x^{1/2}}</math> | <math>\int_{1}^{64}\frac{1}{x^{1/2}}</math> + <math>\int_{1}^{64}\frac{x^{1/3}}{x^{1/2}}</math> | ||
<math>\int_{1}^{64}x^{-1/2}+x^{1/3-1/2}</math> | <math>\int_{1}^{64}x^{-1/2}+x^{1/3-1/2}</math> Add one to the exponents and divide by the new exponent | ||
Revision as of 09:18, 29 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}\frac{1+\sqrt[3]{x}}\sqrt{x}dx}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}\frac{1}{x^{1/2}}} +
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{64}x^{-1/2}+x^{1/3-1/2}} Add one to the exponents and divide by the new exponent