5.4 Indefinite Integrals and the Net Change Theorem/3: Difference between revisions
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& \frac{d}{dx} {[\sin{x} - \frac{1}{3} \sin^3{x} +c]} \\[2ex] | & \frac{d}{dx} {[\sin{x} - \frac{1}{3} \sin^3{x} +c]} \\[2ex] | ||
& {\cos{x} - \frac{1}{3}\cdot 3\sin{x^2} \cos{x} +0} \\[2ex] | & ={\cos{x} - \frac{1}{3}\cdot 3\sin{x^2} \cos{x} +0} \\[2ex] | ||
& \cos{x} - \sin^2{x}\cos{x} \\[2ex] | & =\cos{x} - \sin^2{x}\cos{x} \\[2ex] | ||
& = \cos^3{x} | |||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 19:30, 26 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int\cos^{3}xdx = \sin{x}-\frac{1}{3}\sin^{3}x+C \\[2ex] & \frac{d}{dx} {[\sin{x} - \frac{1}{3} \sin^3{x} +c]} \\[2ex] & ={\cos{x} - \frac{1}{3}\cdot 3\sin{x^2} \cos{x} +0} \\[2ex] & =\cos{x} - \sin^2{x}\cos{x} \\[2ex] & = \cos^3{x} \end{align} }