5.4 Indefinite Integrals and the Net Change Theorem/41: Difference between revisions
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<math>\int_{0}^\frac{1} | <math>\int_{0}^\frac{1}\sqrt{x+1}</math> | ||
Revision as of 19:11, 26 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^\frac{1}\sqrt{x+1}}