5.3 The Fundamental Theorem of Calculus/33: Difference between revisions
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=<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math> | =<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math> | ||
=<math>\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}</math> | =<math>\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}</math> | ||
=<math>/2</math> | |||
Revision as of 18:57, 26 August 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{1}^{2}\left(1+2y^{2}\right)dy} =Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{2}\left(4y^2+4y+1\right)dy} =Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}} =Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle /2}