5.3 The Fundamental Theorem of Calculus/9: Difference between revisions

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<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br>
<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br>
<math>1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)}  
<math>1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)}=
<math>= y^{2} sin{(y)}</math>
y^{2} sin{(y)}</math>

Revision as of 02:50, 26 August 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle g(y)= \int_{2}^{y}t^2\sin{(t)}dt}
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 1\cdot (y^{2}sin{(y)})-0\cdot (2^{2}sin{(2)}=y^{2}sin{(y)}}