6.2 Trigonometric Functions: Unit Circle Approach/14: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 5: | Line 5: | ||
\sin{(t)} &= -\frac{\sqrt{3}}{2} \\[2ex] | \sin{(t)} &= -\frac{\sqrt{3}}{2} & \csc{(t)} &= \frac{1}{2}\\[2ex] | ||
\cos{(t)} &= \frac{1}{2} \\[2ex] | \cos{(t)} &= \frac{1}{2} & \sec{(t)} &= \frac{1}{2}\\[2ex] | ||
\tan{(t)} &= \frac{-\frac{\sqrt{3}}{2}}{\frac{1}{2}} = -\frac{\sqrt{3}}{2}\cdot\frac{2}{1} = -\sqrt{3} \\ | \tan{(t)} &= \frac{-\frac{\sqrt{3}}{2}}{\frac{1}{2}} = -\frac{\sqrt{3}}{2}\cdot\frac{2}{1} = -\sqrt{3} & \\ | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 21:58, 25 August 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\sin {(t)}&=-{\frac {\sqrt {3}}{2}}&\csc {(t)}&={\frac {1}{2}}\\[2ex]\cos {(t)}&={\frac {1}{2}}&\sec {(t)}&={\frac {1}{2}}\\[2ex]\tan {(t)}&={\frac {-{\frac {\sqrt {3}}{2}}}{\frac {1}{2}}}=-{\frac {\sqrt {3}}{2}}\cdot {\frac {2}{1}}=-{\sqrt {3}}&\\\end{aligned}}}