5.3 The Fundamental Theorem of Calculus/33: Difference between revisions
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<math>\frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[\int_{2}^{1/x}\arctan(t)dt\right] | <math>\frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[\int_{2}^{1/x}\arctan(t)dt\right] | ||
< | <math>\frac{-1}{x^2}\left(\arctan(\frac{1}{x}\right)-0</math> | ||
Revision as of 19:51, 25 August 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle h(x)=\int _{2}^{1/x}\arctan(t)dt}
![{\displaystyle {\frac {d}{dx}}\left[h(x)\right]={\frac {d}{dx}}\left[\int _{2}^{1/x}\arctan(t)dt\right]<math>{\frac {-1}{x^{2}}}\left(\arctan({\frac {1}{x}}\right)-0}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/b4a9f0786500550e0c4ff7c3200b1b67f2a83218)