5.3 The Fundamental Theorem of Calculus/33: Difference between revisions
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<math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math> | <math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math> | ||
<math>h'(x)=\frac{-1}{x^2}(arctan(frac{1}{x}-0)</math> | <math>h'(x)=\frac{-1}{x^2}(arctan(\frac{1}{x}-0)</math> | ||
Revision as of 19:43, 25 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle h(x)=\int_{2}^{1/x}\arctan(t)dt}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle h'(x)=\frac{-1}{x^2}(arctan(\frac{1}{x}-0)}